In this chapter, we provide RD Sharma Solutions for Class 9 Chapter 3 Rationalisation Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Class 9 Chapter 3 Rationalisation Maths pdf, free RD Sharma Solutions for Class 9 Chapter 3 Rationalisation Maths book pdf download. Now you will get step by step solution to each question.
RD Sharma Class 9 Solutions Chapter 3 Rationalisation
RD Sharma Class 9 Chapter 3 Rationalisation Ex 3.1
Question 1.
Simplify each of the following:
Solution:
Question 2.
Simplify the following expressions:
(i) (4 + (sqrt { 7 } )) (3 + (sqrt { 2 } ))
(ii) (3 + (sqrt { 3 } ) )(5- (sqrt { 2 } ))
(iii) ((sqrt { 5 } ) -2)((sqrt { 3 } ) – (sqrt { 5 } ))
Solution:
Question 3.
Simplify the following expressions:
(i) (11 + (sqrt { 11 } )) (11 – (sqrt { 11 } ))
(ii) (5 + (sqrt { 7 } ) ) (5 – (sqrt { 7 } ) )
(iii) ((sqrt { 8 } ) – (sqrt { 2 } )) ((sqrt { 8 } )+ (sqrt { 2 } ))
Solution:
Question 4.
Simplify the following expressions:
(i) ((sqrt { 3 } )+(sqrt { 7 } ))2
(ii) ((sqrt { 5 } ) – (sqrt { 3 } ) )2
(iii) (2(sqrt { 5 } ) + 3 (sqrt { 2} ))2
Solution:
RD Sharma Solutions Class 9 Chapter 3 Rationalisation Ex 3.2
Question 1.
Rationalise the denominators of each of the following(i – vii):
Solution:
Question 2.
Find the value to three places of decimals of each of the following. It is given that
Solution:
Question 3.
Express each one of the following with rational denominator:
Solution:
Question 4.
Rationales the denominator and simplify:
Solution:
Question 5.
Simplify:
Solution:
Question 6.
In each of the following determine rational numbers a and b:
Solution:
Question 7.
Solution:
Question 8.
Find the values of each of the following correct to three places of decimals, it being given that (sqrt { 2 } ) = 1.4142, (sqrt { 3 } ) = 1-732, (sqrt { 5 } ) = 2.2360, (sqrt { 6 } ) = 2.4495 and (sqrt { 10 } ) = 3.162.
Solution:
Question 9.
Simplify:
Solution:
Question 10.
Solution:
Question 11.
Solution:
Question 12.
Solution:
Class 9 RD Sharma Solutions Chapter 3 Rationalisation VSAQS
Question 1.
Write the value of (2 + (sqrt { 3 } ) ) (2 – (sqrt { 3 } )).
Solution:
(2+ (sqrt { 3 } ) )(2- (sqrt { 3 } ) ) = (2)2-((sqrt { 3 } ) )2
{∵ (a + b) (a – b) = a2 – b2}
= 4-3=1
Question 2.
Write the reciprocal of 5 + (sqrt { 2 } ).
Solution:
Question 3.
Write the rationalisation factor of 7 – 3(sqrt { 5 } ) .
Solution:
Rationalising factor of 7 – 3(sqrt { 5 } ) is 7 + 3(sqrt { 5 } )
{∵ ((sqrt { a } ) + (sqrt { b } ) ) ((sqrt { a } ) – (sqrt { b } )) = a-b}
Question 4.
Solution:
Question 5.
If x =(sqrt { 2 } ) – 1 then write the value of (frac { 1 }{ x }).
Solution:
Question 6.
If a = (sqrt { 2 } ) + h then find the value of a –(frac { 1 }{ a })
Solution:
Question 7.
If x = 2 + (sqrt { 3 } ), find the value of x + (frac { 1 }{ x }).
Solution:
Question 8.
Write the rationalisation factor of (sqrt { 5 } ) – 2.
Solution:
Rationalisation factor of (sqrt { 5 } ) – 2 is (sqrt { 5 } ) + 2 as
((sqrt { a } ) + (sqrt { b } ))((sqrt { a } ) – (sqrt { b } )) = a – b
Question 9.
Simplify : (sqrt { 3+2sqrt { 2 } }).
Solution:
Question 10.
Simplify : (sqrt { 3-2sqrt { 2 } }).
Solution:
Question 11.
If x = 3 + 2 (sqrt { 2 } ), then find the value of (sqrt { x } ) – (frac { 1 }{ sqrt { x } }).
Solution:
Rationalisation Problems With Solutions PDF RD Sharma Class 9 Solutions MCQS
Mark the correct alternative in each of the following:
Question 1.
Solution:
Question 2.
Solution:
Question 3.
Solution:
Question 4.
The rationalisation factor of 2 + (sqrt { 3 } ) is
(a) 2 – (sqrt { 3 } )
(b) (sqrt { 2 } ) + 3
(c) (sqrt { 2 } ) – 3
(d) (sqrt { 3 } ) – 2
Solution:
Question 5.
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Question 6.
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Question 7.
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Question 8.
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Question 9.
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Question 10.
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Question 11.
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Question 12.
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Question 13.
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Question 14.
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Question 15.
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Question 16.
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Question 17.
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Question 18.
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Question 19.
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Question 20.
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Question 21.
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Question 22.
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Question 23.
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Question 24.
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Question 25.
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All Chapter RD Sharma Solutions For Class 9 Maths
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